Flight
AAL1043 29 Oct 2025
AAL1043, operated by American Airlines, on 29 Oct 2025: Charlotte Douglas International (KCLT) to Cleveland Hopkins International (KCLE), 2 legs. Scheduled and actual times are local to each airport (hover for UTC).
Leg 1 of 2
PlaneTrack receiver network| Route | KCLT CHARLOTTE DOUGLAS INTERNATIONAL → KCLE CLEVELAND HOPKINS INTERNATIONAL |
| Status | Completed (receiver network) |
| First seen airborne | 20:00 EDT 28 Oct |
| Last seen | 21:02 EDT 28 Oct |
| Duration | 1h 01m |
| Aircraft | N805NN |
| Max altitude | 25,000 ft |
| Distance tracked | 374 nm |
Leg 2 of 2estimated
PlaneTrack receiver network| Route | KCLT CHARLOTTE DOUGLAS INTERNATIONAL → ? |
| Status | Completed (receiver network) |
| First seen airborne | 08:17 EDT |
| Last seen | 23:58Z |
| Duration | 11h 40m |
| Aircraft | N805NN |
| Max altitude | 31,750 ft |
Punctuality, last 30 days
| Flights | 5 |
| On time | 0 (0%) |
| Average delay | +71 min |
| Worst delay | +213 min |
In the last 30 days AAL1043 departed on time (within 15 minutes) on 0 of 5 flights (0%), with an average departure delay of +71 min and a worst delay of +213 min.
Schedule, departure and arrival times from the FAA SWIM feed; aircraft, altitude and distance from the PlaneTrack receiver network. On time means a departure within 15 minutes of schedule.