Flight
AAL2505 3 Jul 2026
AAL2505, operated by American Airlines, on 3 Jul 2026: Newark Liberty International (KEWR) to Charlotte Douglas International (KCLT). Scheduled and actual times are local to each airport (hover for UTC).
Flightestimated
PlaneTrack receiver network| Route | KEWR NEWARK LIBERTY INTERNATIONAL → KCLT CHARLOTTE DOUGLAS INTERNATIONAL |
| Status | Completed (receiver network) |
| First seen airborne | 06:09 EDT |
| Last seen | 07:56 EDT |
| Duration | 1h 46m |
| Aircraft | N860NN |
| Max altitude | 36,000 ft |
| Distance tracked | 459 nm |
Punctuality, last 30 days
| Flights | 8 |
| On time | 4 (50%) |
| Average delay | +15 min |
| Worst delay | +30 min |
In the last 30 days AAL2505 departed on time (within 15 minutes) on 4 of 8 flights (50%), with an average departure delay of +15 min and a worst delay of +30 min.
Schedule, departure and arrival times from the FAA SWIM feed; aircraft, altitude and distance from the PlaneTrack receiver network. On time means a departure within 15 minutes of schedule.