Flight
UAL2468 3 Jul 2026
UAL2468, operated by United Airlines, on 3 Jul 2026: Cleveland Hopkins International (KCLE) to Newark Liberty International (KEWR), 2 legs. Scheduled and actual times are local to each airport (hover for UTC).
Leg 1 of 2
PlaneTrack receiver network| Route | KCLE CLEVELAND HOPKINS INTERNATIONAL → KEWR NEWARK LIBERTY INTERNATIONAL |
| Status | Completed (receiver network) |
| First seen airborne | 08:34 EDT |
| Last seen | 10:04 EDT |
| Duration | 1h 29m |
| Aircraft | N17752 |
| Max altitude | 37,000 ft |
| Distance tracked | 350 nm |
Leg 2 of 2estimated
PlaneTrack receiver network| Route | KCLE CLEVELAND HOPKINS INTERNATIONAL → KMSY LOUIS ARMSTRONG NEW ORLEANS INTERNATIONAL |
| Status | Completed (receiver network) |
| First seen airborne | 12:51 EDT |
| Last seen | 14:54 CDT |
| Duration | 3h 03m |
| Aircraft | N895UA |
| Max altitude | 35,975 ft |
| Distance tracked | 797 nm |
Punctuality, last 30 days
| Flights | 13 |
| On time | 8 (62%) |
| Average delay | +29 min |
| Worst delay | +185 min |
In the last 30 days UAL2468 departed on time (within 15 minutes) on 8 of 13 flights (62%), with an average departure delay of +29 min and a worst delay of +185 min.
Schedule, departure and arrival times from the FAA SWIM feed; aircraft, altitude and distance from the PlaneTrack receiver network. On time means a departure within 15 minutes of schedule.